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Karnataka Board PUCPUC Science 2nd PUC Class 12

Write the structure of the major organic product in the following reaction: CH3CH = C(CH3)2 + HBr →

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Question

Write the structure of the major organic product in the following reaction:

\[\ce{CH3CH = C(CH3)2 + HBr ->}\]

Chemical Equations/Structures
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Solution 1

\[\begin{array}{cc}
\phantom{..}\ce{CH3}\phantom{......................................}\ce{CH3}\\
\phantom{.}|\phantom{..........................................}|\phantom{..}\\
\ce{CH3 - CH = C - CH3 + HBr ->[Markovnikov’s][addition] CH3 - CH2 - C - CH3}\phantom{........}\\
\phantom{..........................................}|\\
\phantom{...........................................}\ce{\underset{2-Bromo-2-methylbutane}{Br}}
\end{array}\]

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Solution 2

\[\ce{\underset{2-mrthyl-2-butene}{CH3CH = C(CH3)2} + HBr ->\underset{2-Bromo-2-methylbutane}{CH3CH2C(Br)(CH3)2}}\]

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Chapter 6: Haloalkanes and Haloarenes - Exercises [Page 190]

APPEARS IN

NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 6 Haloalkanes and Haloarenes
Exercises | Q 6.14 (viii) | Page 190

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\[\begin{array}{cc}
\ce{H3C}\phantom{..................................}\\
\backslash\phantom{...........................}\\
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/\phantom{...........................}\\
\ce{H3C}\phantom{...................................}
\end{array}\]


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