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Write the Order and Degree of the Differential Equation Y = X D Y D X + a √ 1 + ( D Y D X ) 2

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Question

Write the order and degree of the differential equation
\[y = x\frac{dy}{dx} + a\sqrt{1 + \left( \frac{dy}{dx} \right)^2}\]

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Solution

We have,
\[y = x\frac{dy}{dx} + a\sqrt{1 + \left( \frac{dy}{dx} \right)^2}\]
\[y - x\frac{dy}{dx} = a\sqrt{1 + \left( \frac{dy}{dx} \right)^2}\]
Squaring both sides, we get
\[ \left( y - x\frac{dy}{dx} \right)^2 = \left\{ a\sqrt{1 + \left( \frac{dy}{dx} \right)^2} \right\}^2 \]
\[ y^2 + x^2 \left( \frac{dy}{dx} \right)^2 - 2xy\frac{dy}{dx} = a^2 \left\{ 1 + \left( \frac{dy}{dx} \right)^2 \right\}\]
\[ y^2 + \left( \frac{dy}{dx} \right)^2 \left\{ x^2 - a^2 \right\} - 2xy\frac{dy}{dx} = a^2 \]
From the above equation, we see that the highest order is 1 . 
So, its order is 1 and the power of the highest order derivative is 2 . 
Thus, it is a differential equation of order 1 and degree 2 .

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Chapter 21: Differential Equations - Very Short Answers [Page 138]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 21 Differential Equations
Very Short Answers | Q 9 | Page 138

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