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Question
Write balanced chemical equation for the following word equation.
Lead nitrate + Potassium iodide → Lead iodide + Potassium nitrate
Is this a double displacement reaction? Justify your answer. Name the compound precipitated and write the ions present in it.
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Solution
The balanced chemical equation for the reaction between lead nitrate and potassium iodide is:
\[\ce{Pb(NO3)2(aq) + 2KI(aq)->PbI2(s) + 2KNO3(aq)}\]
This reaction is indeed a double displacement reaction, as it involves the exchange of ions between the two reacting compounds. In a double displacement reaction, the anions and cations of two different reactants switch places, forming two new compounds. Here, the nitrate ions (NO3−) from lead nitrate switch places with the iodide ions (I−) from potassium iodide, resulting in the formation of lead iodide (PbI2) and potassium nitrate (KNO3). The compound that precipitates (forms a solid) in this reaction is lead iodide (PbI2), and the ions present in it are lead ions (Pb2+) and iodide ions (I−).
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