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प्रश्न
Write balanced chemical equation for the following word equation.
Lead nitrate + Potassium iodide → Lead iodide + Potassium nitrate
Is this a double displacement reaction? Justify your answer. Name the compound precipitated and write the ions present in it.
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उत्तर
The balanced chemical equation for the reaction between lead nitrate and potassium iodide is:
\[\ce{Pb(NO3)2(aq) + 2KI(aq)->PbI2(s) + 2KNO3(aq)}\]
This reaction is indeed a double displacement reaction, as it involves the exchange of ions between the two reacting compounds. In a double displacement reaction, the anions and cations of two different reactants switch places, forming two new compounds. Here, the nitrate ions (NO3−) from lead nitrate switch places with the iodide ions (I−) from potassium iodide, resulting in the formation of lead iodide (PbI2) and potassium nitrate (KNO3). The compound that precipitates (forms a solid) in this reaction is lead iodide (PbI2), and the ions present in it are lead ions (Pb2+) and iodide ions (I−).
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संबंधित प्रश्न
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What type of chemical reaction is represented by the following equation?
PQ + RS → PS + RQ
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(a) What is metal X?
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(c) Name the compound Y.
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(e) What type of chemical reaction is illustrated by the above equation?
In a double displacement reaction such as the reaction between sodium sulphate solution and barium chloride solution:
- exchange of atoms takes place
- exchange of ions takes place
- a precipitate is produced
- an insoluble salt is produced
The correct option is:
When a potassium iodide solution is added to a solution of lead (II) nitrate in a test tube, a precipitate is formed.
List two types of reactions in which this reaction can be placed.
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Which among the following is (are) double displacement reaction(s)?
(i) \[\ce{Pb + CuCl -> PbCl2 + Cu}\]
(ii) \[\ce{Na2SO4 + BaCl2 -> BaSO4 + 2NaCl}\]
(iii) \[\ce{C + O2 -> CO2}\]
(iv) \[\ce{CH4 + 2O2 -> CO2 + 2H2O}\]
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(i) Displacement reaction
(ii) Precipitation reaction
(iii) Combination reaction
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Give scientific reason.
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