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Question
Identify the type of reaction taking place in the following case and write the balanced chemical equation for the reaction.
Potassium iodide reacts with lead nitrate to produce potassium nitrate and lead iodide.
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Solution
The given reaction is a double displacement reaction.
\[\ce{2Kl(aq) + Pb(NO3)2(aq)->2KNO3(aq) + Pbl2(s)}\]
RELATED QUESTIONS
Complete the following reaction, balance it and write the name of the products CuO + HCI →_________ + _________
Give an example of a double displacement reaction other than the one given in the following Activity.
•Take about 3 mL of sodium sulphate
solution in a test tube.
• In another test tube, take about 3 mL of
barium chloride solution.
• Mix the two solutions given in the following fig.
• What do you observe?
Write the balanced chemical equation for the following and identify the type of reaction.
\[\ce{Potassium bromide (aq) + Barium iodide (aq) -> Potassium iodide (aq) + Barium bromide (s)}\]
A metal X forms a water soluble salt XNO3. When an aqueous solution of XNO3 is added to common salt solution, then a white precipitate of compound Y is formed alongwith sodium nitrate solution. Metal X is said to be the best conductor of electricity and it does not evolve hydrogen when put in dilute hydrohloric acid.
(a) What is metal X?
(b) What is salt XNO3?
(c) Name the compound Y.
(d) Write the chemical equation of the reaction which takes place on reacting XNO3 solution and common salt solution giving the physical states of all the reactants and products.
(e) What type of chemical reaction is illustrated by the above equation?
The aqueous solutions of copper sulphate and zinc sulphate appear
(A) blue and green respectively
(B) green and colourless respectively
(C) blue and brown respectively
(D) blue and colourless respectively.
When a potassium iodide solution is added to a solution of lead (II) nitrate in a test tube, a precipitate is formed.
List two types of reactions in which this reaction can be placed.
Explain the types of double displacement reactions with examples.
Which option denotes a double displacement reaction?
Which among the following is (are) double displacement reaction(s)?
(i) \[\ce{Pb + CuCl -> PbCl2 + Cu}\]
(ii) \[\ce{Na2SO4 + BaCl2 -> BaSO4 + 2NaCl}\]
(iii) \[\ce{C + O2 -> CO2}\]
(iv) \[\ce{CH4 + 2O2 -> CO2 + 2H2O}\]
Give scientific reason.
While preparing dilute sulphuric acid from concentrated sulphuric acid in the laboratory, the concentrated sulphuric acid is added slowly to water with constant stirring.
