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Without expanding the determinants, show that |xaybzca2b2c2111|=|xyzabcbccaab|

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Question

Without expanding the determinants, show that `|(x"a", y"b", z"c"),("a"^2, "b"^2, "c"^2),(1, 1, 1)| = |(x, y, z),("a", "b", "c"),("bc", "ca", "ab")|`

Sum
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Solution

L.H.S. = `|(x"a", y"b", z"c"),("a"^2, "b"^2, "c"^2),(1, 1, 1)|`

= Taking a, b, c common from C1, C2, C3 respectively, we get

L.H.S. = `"abc"|(x, y, z),("a", "b", "c"),(1/"a", 1/"b", 1/"c")|`

= `|(x, y, z),("a", "b", "c"),("abc"/"a", "abc"/"b", "abc"/"c")|`

= `|(x, y, z),("a", "b", "c"),("bc", "ca", "ab")|`

= R.H.S.

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Chapter 6: Determinants - MISCELLANEOUS EXERCISE - 6 [Page 95]

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Balbharati Mathematics and Statistics (Commerce) Part 1 [English] Standard 11 Maharashtra State Board
Chapter 6 Determinants
MISCELLANEOUS EXERCISE - 6 | Q 4) ii) | Page 95
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