Question

Why is the mechanical advantage of a lever of the second order always greater than one?

Answer 1

In a second-order lever, the load lies between the fulcrum and the effort.

Therefore, the effort arm is always longer than the load arm.

`M. A. = "Effort arm"/"Load arm"`

Since the effort arm is greater than the load arm,

M. A. > 1

Hence, the mechanical advantage of a second-order lever is always greater than one.