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प्रश्न
Why is the mechanical advantage of a lever of the second order always greater than one?
लघु उत्तरीय
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उत्तर
In a second-order lever, the load lies between the fulcrum and the effort.
Therefore, the effort arm is always longer than the load arm.
`M. A. = "Effort arm"/"Load arm"`
Since the effort arm is greater than the load arm,
M. A. > 1
Hence, the mechanical advantage of a second-order lever is always greater than one.
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