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Question
When \[\ce{Cu^2+}\] ion is treated with \[\ce{KI}\], a white precipitate is formed. Explain the reaction with the help of chemical equation.
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Solution
Reduction of \[\ce{Cu^2+}\] to \[\ce{Cu^+}\] takes place due to reaction with F ions.
This is given by the equation.
\[\ce{2Cu^2+ + 4I^- -> \underset{(White precipitate)}{Cu2I2 + I2}}\]
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