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Question
When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by 10∘C. What is the specific heat of the substance?
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Solution
Let the specific heat capacity of the substance be c.
Given: Mass of the substance, m = 3 kg = 3000 g
Heat given to the substance, Q = 600 cal
Increase in temperature of the substance = 10∘C
Now, the amount of heat in a body is given as
`"Q" = "m" xx "c" xx triangle "T"`
`=> "c" = "Q"/("m" xx triangle "T") = 600/(3000 xx 10) = 0.02 "cal" g^(-1) ° C^(-1)`
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