Question

When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by 10°C. What is the specific heat of the substance?

Answer 1

Given: Mass of the substance (m) = 3 kg = 3000 g

Heat given to the substance (Q) = 600 cal

Increase in temperature of the substance = 10°C

Let the specific heat capacity of the substance be c.

Now, the amount of heat in a body is given as:

Q = m × c × ΔT

⇒ c = `Q/(m xx Delta T)`

= `600/(3000 xx 10)`

= 0.02 cal g⁻¹°C⁻¹