Question

When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by 10^∘C. What is the specific heat of the substance?

Answer 1

Let the specific heat capacity of the substance be c.

Given: Mass of the substance, m = 3 kg = 3000 g

Heat given to the substance, Q = 600 cal

Increase in temperature of the substance = 10^∘C

Now, the amount of heat in a body is given as 

`"Q" = "m" xx "c" xx triangle "T"`

`=> "c" = "Q"/("m" xx triangle "T") = 600/(3000 xx 10) = 0.02  "cal"  g^(-1) ° C^(-1)`