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प्रश्न
When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by 10°C. What is the specific heat of the substance?
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उत्तर
Given: Mass of the substance (m) = 3 kg = 3000 g
Heat given to the substance (Q) = 600 cal
Increase in temperature of the substance = 10°C
Let the specific heat capacity of the substance be c.
Now, the amount of heat in a body is given as:
Q = m × c × ΔT
⇒ c = `Q/(m xx Delta T)`
= `600/(3000 xx 10)`
= 0.02 cal g−1°C−1
संबंधित प्रश्न
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Analogy
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