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What is the smallest value of x in the following inequation? 20 – 5x < 5(x + 8) and x ∈ I

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Question

What is the smallest value of x in the following inequation?

20 – 5x < 5(x + 8) and x ∈ I

Options

  • –1

  • 0

  • 1

  • cannot be determined

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Solution

–1

Explanation:

⇒ 20 – 5x < 5(x + 8)

⇒ 20 – 5x < 5x + 40

⇒ 5x + 40 > 20 – 5x

⇒ 5x + 5x > 20 – 40

⇒ 10x > 20 – 40

⇒ 10x > –20

⇒ `x > - 20/10`

⇒ x > –2

Since, x ∈ I and x > –2

⇒ Smallest value of x in following inequation = –1.

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Chapter 4: Linear Inequations - EXERCISE 4 [Page 43]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 4 Linear Inequations
EXERCISE 4 | Q 23. | Page 43
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