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प्रश्न
What is the smallest value of x in the following inequation?
20 – 5x < 5(x + 8) and x ∈ I
विकल्प
–1
0
1
cannot be determined
MCQ
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उत्तर
–1
Explanation:
⇒ 20 – 5x < 5(x + 8)
⇒ 20 – 5x < 5x + 40
⇒ 5x + 40 > 20 – 5x
⇒ 5x + 5x > 20 – 40
⇒ 10x > 20 – 40
⇒ 10x > –20
⇒ `x > - 20/10`
⇒ x > –2
Since, x ∈ I and x > –2
⇒ Smallest value of x in following inequation = –1.
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