Question

What is the smallest value of x in the following inequation?

20 – 5x < 5(x + 8) and x ∈ I

पर्याय

• –1

• 0

• 1

• cannot be determined

Answer 1

–1

Explanation:

⇒ 20 – 5x < 5(x + 8)

⇒ 20 – 5x < 5x + 40

⇒ 5x + 40 > 20 – 5x

⇒ 5x + 5x > 20 – 40

⇒ 10x > 20 – 40

⇒ 10x > –20

⇒ `x > - 20/10`

⇒ x > –2

Since, x ∈ I and x > –2

⇒ Smallest value of x in following inequation = –1.