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What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1024 kg and radius of the earth is 6.4 × 106 m).

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Question

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 1024 kg and radius of the earth is 6.4 × 106 m).

Numerical
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Solution

Mass of the earth (M) = 6 × 1024 kg 

Radius of the Earth (R) = 6.4 × 106 m

Mass of the object (m) = 1kg

Universal constant (G) = `6.67 × 10^-11 (Nm)^2/(kg)^2`

We know that, F = `(GM_eM_(body))/r_e^2`

F = `(6.67×10^-11 × 6×10^24 × 1)/(6.4×10^6)^2`

This gives, F = 9.8 N

Hence the gravitational force between the object and the earth = 9.8 N.

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Chapter 9: Gravitation - Exercises [Page 111]

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NCERT Science [English] Class 9
Chapter 9 Gravitation
Exercises | Q 3. | Page 111

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