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Question
What is Kc for the following equilibrium when the equilibrium concentration of each substance is: [SO2] = 0.60 M, [O2] = 0.82 M and [SO3] = 1.90 M?
\[\ce{2SO2(g) + O2(g) ⇌ 2SO3(g)}\]
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Solution
The equilibrium constant (Kc) for the give reaction is:
`"K"_"c" = ["SO"_3]^2/(["SO"_2]^2["O"_2])`
`= ((1.90)^2 "M"^2)/((0.60)^2 (0.821)"M"^3)`
`= 12.239 " M"^(-1) ("approximately")`
Hence, Kc for the equilibrium is `12.239 " M"^(-1)`
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