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What is Kc for the following equilibrium when the equilibrium concentration of each substance is: [SO2] = 0.60 M, [O2] = 0.82 M and [SO3] = 1.90 M? 2SOX2(g)+OX2(g)↽−−⇀2SOX3(g)

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प्रश्न

What is Kc for the following equilibrium when the equilibrium concentration of each substance is: [SO2] = 0.60 M, [O2] = 0.82 M and [SO3] = 1.90 M?

\[\ce{2SO2(g) + O2(g) ⇌ 2SO3(g)}\]

संख्यात्मक
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उत्तर

The equilibrium constant (Kc) for the give reaction is:

`"K"_"c" = ["SO"_3]^2/(["SO"_2]^2["O"_2])`

`= ((1.90)^2 "M"^2)/((0.60)^2 (0.821)"M"^3)`

`= 12.239 " M"^(-1) ("approximately")`

Hence, Kc for the equilibrium is `12.239 " M"^(-1)`

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Law of Chemical Equilibrium and Equilibrium Constant
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अध्याय 6: Equilibrium - EXERCISES [पृष्ठ २३२]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 11
अध्याय 6 Equilibrium
EXERCISES | Q 7.2 | पृष्ठ २३२

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