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What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistance 4 Ω, 8 Ω, 12 Ω, 24 Ω?

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Question

What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistance 4 Ω, 8 Ω, 12 Ω, 24 Ω?

Numerical
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Solution

There are four coils of resistances: 4 Ω, 8 Ω, 12 Ω and 24 Ω, respectively.

(a) If these coils are connected in series, then the equivalent resistance will be the highest, given by the sum 4 + 8 + 12 + 24 = 48 Ω

(b) If these coils are connected in parallel, then the equivalent resistance will be the lowest, given by,

`1/(1/4+1/8+1/12+1/24)=1/((6+3+2+1)/24)=24/12=2 Omega`

Therefore, 2 Ω is the lowest total resistance.

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Chapter 11: Electricity - Intext Questions [Page 188]

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NCERT Science [English] Class 10
Chapter 11 Electricity
Intext Questions | Q 18. | Page 188

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Use the data in the Table given below to answer the following –

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Electrical resistivity of some substances at 20°C
Material Resistivity (Ω m)
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Silver 1.60 × 10−8
Copper 1.62 × 10−8
Aluminium 2.63 × 10−8
Tungsten 5.20 × 10−8
Nickel 6.84 × 10−8
Iron 10.0 × 10−8
Chromium 12.9 × 10−8
Mercury 94.0 × 10−8
Manganese 1.84 × 10−6
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Constantan
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Manganin
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44 × 10−6
Nichrome
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100 × 10−6
Insulators Glass 1010 − 1014
Hard rubber 1013 − 1016
Ebonite 1015 − 1017
Diamond 1012 − 1013
Paper (dry) 1012

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