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Question
What inspired N. Bartlett for carrying out reaction between Xe and PtF6?
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Solution
PtF6 interacts with oxygen to generate \[\ce{O^+_2[PtF6]-}\], according to N. Bartlett's 1962 discovery. Because the first ionisation enthalpy of Xe (1170 kJ mol−1) is so near to that of the O2 molecule (1175 kJ), Bartlett was motivated to conduct a reaction with Xe and PtF6. He was successful in isolating the orange-yellow complex XePtF6.
\[\ce{Xe + PtF6 ->[278 K] XePtF6}\]
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| Column I | Column II |
| (A) XeF6 | (1) sp3d3 – distorted octahedral |
| (B) XeO3 | (2) sp3d2 – square planar |
| (C) XeOF4 | (3) sp3 – pyramidal |
| (D) XeF4 | (4) sp3d2 – square pyramidal |
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| List - I | List - II | ||
| (Species) | (Number of lone pairs of electrons on the central atom) |
||
| (A) | XeF2 | (i) | 0 |
| (B) | XeO2F2 | (ii) | 1 |
| (C) | XeO3F2 | (iii) | 2 |
| (D) | XeF4 | (iv) | 3 |
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\[\ce{XeF6 + H2O ->[Partial][Hydrolysis] \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}}\]
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