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Question
Complete the following equations : XeF4 + O2F2→
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Solution
XeF6 can be prepared by the interaction of XeF4 and O2F2 at 143 K.
XeF4 + O2F2 → XeF6 + O2
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Match List - I with List - II:
| List - I | List - II | ||
| (Species) | (Number of lone pairs of electrons on the central atom) |
||
| (A) | XeF2 | (i) | 0 |
| (B) | XeO2F2 | (ii) | 1 |
| (C) | XeO3F2 | (iii) | 2 |
| (D) | XeF4 | (iv) | 3 |
Choose the most appropriate answer from the options given below:
