Advertisements
Advertisements
प्रश्न
Complete the following equations : XeF4 + O2F2→
Advertisements
उत्तर
XeF6 can be prepared by the interaction of XeF4 and O2F2 at 143 K.
XeF4 + O2F2 → XeF6 + O2
APPEARS IN
संबंधित प्रश्न
Draw the structures of the following molecules: XeF2
Write the structures of the following molecule:
XeOF4
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{IBr^-_2}\]
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{BrO^-_3}\]
Complete the following reactions : XeF6 + 3H2O →
The number of lone pairs of electrons present in ClF5:
In which of the following pairs, the two species are isostructural:
Substance having the lowest boiling point ______.
The atomic radii of Zr and Hf are almost identical. This is because of
Match List - I with List - II:
| List - I | List - II | ||
| (Species) | (Number of lone pairs of electrons on the central atom) |
||
| (A) | XeF2 | (i) | 0 |
| (B) | XeO2F2 | (ii) | 1 |
| (C) | XeO3F2 | (iii) | 2 |
| (D) | XeF4 | (iv) | 3 |
Choose the most appropriate answer from the options given below:
