Advertisements
Advertisements
प्रश्न
Complete the following equations : XeF4 + O2F2→
Advertisements
उत्तर
XeF6 can be prepared by the interaction of XeF4 and O2F2 at 143 K.
XeF4 + O2F2 → XeF6 + O2
APPEARS IN
संबंधित प्रश्न
Draw the structure of the following:
XeO3
How are xenon fluorides XeF2, XeF4 and XeF6 obtained?
Which one of the following does not exist?
Complete the following reactions:
XeF6+2H2O ----->
Draw structure and name the shape of bromine trifluoride.
Which of the following fluorides does not exist?
Match the compounds given in Column I with the hybridisation and shape given in Column II and mark the correct option.
| Column I | Column II |
| (A) XeF6 | (1) sp3d3 – distorted octahedral |
| (B) XeO3 | (2) sp3d2 – square planar |
| (C) XeOF4 | (3) sp3 – pyramidal |
| (D) XeF4 | (4) sp3d2 – square pyramidal |
The order of increasing sizes of atomic radii among the elements O, S, Se and As is:
\[\ce{XeF6 + H2O ->[Partial][Hydrolysis] \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}}\]
Write two uses of neon.
