Advertisements
Advertisements
प्रश्न
What inspired N. Bartlett for carrying out reaction between Xe and PtF6?
Advertisements
उत्तर
PtF6 interacts with oxygen to generate \[\ce{O^+_2[PtF6]-}\], according to N. Bartlett's 1962 discovery. Because the first ionisation enthalpy of Xe (1170 kJ mol−1) is so near to that of the O2 molecule (1175 kJ), Bartlett was motivated to conduct a reaction with Xe and PtF6. He was successful in isolating the orange-yellow complex XePtF6.
\[\ce{Xe + PtF6 ->[278 K] XePtF6}\]
संबंधित प्रश्न
Complete the following equations : XeF4 + O2F2→
Draw the structure of the following:
XeO3
test q 1234
Why has it been difficult to study the chemistry of radon?
Write electronic configuration and two uses of neon. (Z = 10)
Complete the given chemical equations:
`2XeF_2 + 2H_2O->`
Complete the following reactions : XeF6 + 3H2O →
Complete the following reactions:
XeF6+2H2O ----->
Write the electronic configuration of the following element:
Krypton (Z = 36)
Draw the structure of XeF4.
Partial hydrolysis of XeF4 gives ____________.
Which of the following reactions is an example of redox reaction?
Substance having the lowest boiling point ______.
On partial hydrolysis, XeF6 gives ______.
Match List - I with List - II:
| List - I | List - II | ||
| (Species) | (Number of lone pairs of electrons on the central atom) |
||
| (A) | XeF2 | (i) | 0 |
| (B) | XeO2F2 | (ii) | 1 |
| (C) | XeO3F2 | (iii) | 2 |
| (D) | XeF4 | (iv) | 3 |
Choose the most appropriate answer from the options given below:
Discuss the trends in electronegativity and atomic radii for elements of group 16 17, 18.
The element expected to form the largest ion to achieve the nearest noble gas configuration is:
