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प्रश्न
What inspired N. Bartlett for carrying out reaction between Xe and PtF6?
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उत्तर
PtF6 interacts with oxygen to generate \[\ce{O^+_2[PtF6]-}\], according to N. Bartlett's 1962 discovery. Because the first ionisation enthalpy of Xe (1170 kJ mol−1) is so near to that of the O2 molecule (1175 kJ), Bartlett was motivated to conduct a reaction with Xe and PtF6. He was successful in isolating the orange-yellow complex XePtF6.
\[\ce{Xe + PtF6 ->[278 K] XePtF6}\]
संबंधित प्रश्न
Draw the structures of the following molecules: XeF2
Complete the following equation:
\[\ce{XeF2 + H2O ->}\]
Draw the structure of the following:
XeO3
How are XeO3 and XeOF4 prepared?
Which one of the following does not exist?
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{ICI^-_4}\]
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{BrO^-_3}\]
Complete the following reactions : XeF6 + 3H2O →
Complete the following reactions:
XeF6+2H2O ----->
Draw the structures of the following
XeF6
Write the electronic configuration of the following element:
Krypton (Z = 36)
Draw the structure of XeF4.
Sulfur dioxide reacts with sodium hydroxide solution to form _______.
Explain the trend in the following atomic properties of group 16 elements:
Electron gain enthalpy
Which of the following fluorides does not exist?
Partial hydrolysis of XeF4 gives ____________.
Noble gases are named because of their inertness towards reactivity. Identify an incorrect statement about them.
\[\ce{XeF6 + H2O ->[Partial][Hydrolysis] \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}}\]
Write two uses of neon.
The element expected to form the largest ion to achieve the nearest noble gas configuration is:
