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प्रश्न
What inspired N. Bartlett for carrying out reaction between Xe and PtF6?
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उत्तर
PtF6 interacts with oxygen to generate \[\ce{O^+_2[PtF6]-}\], according to N. Bartlett's 1962 discovery. Because the first ionisation enthalpy of Xe (1170 kJ mol−1) is so near to that of the O2 molecule (1175 kJ), Bartlett was motivated to conduct a reaction with Xe and PtF6. He was successful in isolating the orange-yellow complex XePtF6.
\[\ce{Xe + PtF6 ->[278 K] XePtF6}\]
संबंधित प्रश्न
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test q 1234
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| Column I | Column II |
| (A) XeF6 | (1) sp3d3 – distorted octahedral |
| (B) XeO3 | (2) sp3d2 – square planar |
| (C) XeOF4 | (3) sp3 – pyramidal |
| (D) XeF4 | (4) sp3d2 – square pyramidal |
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