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प्रश्न
What inspired N. Bartlett for carrying out reaction between Xe and PtF6?
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उत्तर
PtF6 interacts with oxygen to generate \[\ce{O^+_2[PtF6]-}\], according to N. Bartlett's 1962 discovery. Because the first ionisation enthalpy of Xe (1170 kJ mol−1) is so near to that of the O2 molecule (1175 kJ), Bartlett was motivated to conduct a reaction with Xe and PtF6. He was successful in isolating the orange-yellow complex XePtF6.
\[\ce{Xe + PtF6 ->[278 K] XePtF6}\]
संबंधित प्रश्न
Account for the following:
Helium is used in diving apparatus.
Draw the structures of the following molecules: XeF2
Draw the structure of the following:
XeO3
Balance the following equation:
\[\ce{XeF6 + H2O -> XeO2F2 + HF}\]
How are xenon fluorides XeF2, XeF4 and XeF6 obtained?
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{ICI^-_4}\]
Complete the given chemical equations:
`2XeF_2 + 2H_2O->`
Draw the structures of the following
XeF6
Fill in the blanks by choosing the appropriate word/words from the brackets
(square pyramidal, electrical, 74; 26, sp3d2, sp3d, chemical, 68, 32, tetrahedral, yellow, white, iodoform, Lucas)
The geometry of XeOF4 molecule is ______ and the hybridisation of Xenon atom in the molecule is ________.
The number of lone pairs of electrons present in ClF5:
Partial hydrolysis of XeF4 gives ____________.
Helium is preferred to be used in balloons instead of hydrogen because it is ____________.
In which of the following pairs, the two species are isostructural:
On partial hydrolysis, XeF6 gives ______.
Which one of the following reactions of xenon compounds is not feasible?
\[\ce{XeF6 + H2O ->[Partial][Hydrolysis] \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}}\]
\[\ce{XeF4 + H2O - \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}}\]
Discuss the trends in electronegativity and atomic radii for elements of group 16 17, 18.
The element expected to form the largest ion to achieve the nearest noble gas configuration is:
