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प्रश्न
How are xenon fluorides XeF2, XeF4 and XeF6 obtained?
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उत्तर
Xenon fluorides are obtained by the direct reaction of xenon (Xe) with fluorine gas (F2). The product formed depends on the reaction conditions, such as temperature, pressure, and the ratio of Xe to F2:
1. Formation of XeF2:
\[\ce{Xe + F2 -> XeF2}\] (673 K, 1 bar, excess Xe)
2. Formation of XeF4:
\[\ce{Xe + 2F2 -> XeF4}\] (873 K, 7 bar, 1 : 5 ratio)
3. Formation of XeF6:
\[\ce{Xe + 3F2 -> XeF6}\] (573 K, 60–70 bar, 1:20 ratio)
संबंधित प्रश्न
Account for the following:
Helium is used in diving apparatus.
Which noble gas has the lowest boiling point?
Draw the structure of the following:
XeO3
test q 1234
What inspired N. Bartlett for carrying out reaction between Xe and PtF6?
How are XeO3 and XeOF4 prepared?
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{ICI^-_4}\]
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`2XeF_2 + 2H_2O->`
Draw structures of the following:
XeF4
Draw the structure of XeF4.
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Draw structure and name the shape of bromine trifluoride.
Helium is preferred to be used in balloons instead of hydrogen because it is ____________.
Match List - I with List - II:
| List - I | List - II | ||
| (Species) | (Number of lone pairs of electrons on the central atom) |
||
| (A) | XeF2 | (i) | 0 |
| (B) | XeO2F2 | (ii) | 1 |
| (C) | XeO3F2 | (iii) | 2 |
| (D) | XeF4 | (iv) | 3 |
Choose the most appropriate answer from the options given below:
Which one of the following reactions of xenon compounds is not feasible?
\[\ce{XeF4 + H2O - \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}}\]
Discuss the trends in electronegativity and atomic radii for elements of group 16 17, 18.
Write two uses of neon.
