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प्रश्न
How are xenon fluorides XeF2, XeF4 and XeF6 obtained?
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उत्तर
Xenon fluorides are obtained by the direct reaction of xenon (Xe) with fluorine gas (F2). The product formed depends on the reaction conditions, such as temperature, pressure, and the ratio of Xe to F2:
1. Formation of XeF2:
\[\ce{Xe + F2 -> XeF2}\] (673 K, 1 bar, excess Xe)
2. Formation of XeF4:
\[\ce{Xe + 2F2 -> XeF4}\] (873 K, 7 bar, 1 : 5 ratio)
3. Formation of XeF6:
\[\ce{Xe + 3F2 -> XeF6}\] (573 K, 60–70 bar, 1:20 ratio)
संबंधित प्रश्न
Draw the structures of the following molecules: XeF2
Complete the equation : XeF2+PF5 →
Write the structures of the following molecule:
XeOF4
Complete the following equations : XeF4 + O2F2→
Draw the structure of the following:
XeO3
test q 1234
What inspired N. Bartlett for carrying out reaction between Xe and PtF6?
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{ICI^-_4}\]
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{IBr^-_2}\]
Answer the following.
List the uses of Neon and argon gases.
Complete the following reactions:
XeF6+2H2O ----->
Draw the structures of the following
XeF6
Fill in the blanks by choosing the appropriate word/words from the brackets
(square pyramidal, electrical, 74; 26, sp3d2, sp3d, chemical, 68, 32, tetrahedral, yellow, white, iodoform, Lucas)
The geometry of XeOF4 molecule is ______ and the hybridisation of Xenon atom in the molecule is ________.
Draw structures of the following:
XeF4
The number of lone pairs of electrons present in ClF5:
Which one of the following reactions of xenon compounds is not feasible?
\[\ce{XeF4 + H2O - \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}}\]
