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प्रश्न
How are xenon fluorides XeF2, XeF4 and XeF6 obtained?
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उत्तर
Xenon fluorides are obtained by the direct reaction of xenon (Xe) with fluorine gas (F2). The product formed depends on the reaction conditions, such as temperature, pressure, and the ratio of Xe to F2:
1. Formation of XeF2:
\[\ce{Xe + F2 -> XeF2}\] (673 K, 1 bar, excess Xe)
2. Formation of XeF4:
\[\ce{Xe + 2F2 -> XeF4}\] (873 K, 7 bar, 1 : 5 ratio)
3. Formation of XeF6:
\[\ce{Xe + 3F2 -> XeF6}\] (573 K, 60–70 bar, 1:20 ratio)
संबंधित प्रश्न
Account for the following:
Helium is used in diving apparatus.
Complete the equation : XeF2+PF5 →
Write the structures of the following molecule:
XeOF4
Complete the following equation:
\[\ce{XeF2 + H2O ->}\]
Why has it been difficult to study the chemistry of radon?
What inspired N. Bartlett for carrying out reaction between Xe and PtF6?
Which one of the following does not exist?
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{IBr^-_2}\]
Complete the following reactions : XeF6 + 3H2O →
Partial hydrolysis of XeF4 gives ____________.
Helium is preferred to be used in balloons instead of hydrogen because it is ____________.
Substance having the lowest boiling point ______.
The order of increasing sizes of atomic radii among the elements O, S, Se and As is:
Which one of the following reactions of xenon compounds is not feasible?
\[\ce{XeF4 + H2O - \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}}\]
Discuss the trends in electronegativity and atomic radii for elements of group 16 17, 18.
Write two uses of neon.
The element expected to form the largest ion to achieve the nearest noble gas configuration is:
