Advertisements
Advertisements
प्रश्न
How are xenon fluorides XeF2, XeF4 and XeF6 obtained?
Advertisements
उत्तर
Xenon fluorides are obtained by the direct reaction of xenon (Xe) with fluorine gas (F2). The product formed depends on the reaction conditions, such as temperature, pressure, and the ratio of Xe to F2:
1. Formation of XeF2:
\[\ce{Xe + F2 -> XeF2}\] (673 K, 1 bar, excess Xe)
2. Formation of XeF4:
\[\ce{Xe + 2F2 -> XeF4}\] (873 K, 7 bar, 1 : 5 ratio)
3. Formation of XeF6:
\[\ce{Xe + 3F2 -> XeF6}\] (573 K, 60–70 bar, 1:20 ratio)
APPEARS IN
संबंधित प्रश्न
Draw the structures of the following molecules: XeF2
Complete the following equation:
\[\ce{XeF2 + H2O ->}\]
Balance the following equation:
\[\ce{XeF6 + H2O -> XeO2F2 + HF}\]
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{BrO^-_3}\]
Fill in the blanks by choosing the appropriate word/words from the brackets
(square pyramidal, electrical, 74; 26, sp3d2, sp3d, chemical, 68, 32, tetrahedral, yellow, white, iodoform, Lucas)
The geometry of XeOF4 molecule is ______ and the hybridisation of Xenon atom in the molecule is ________.
Draw structures of the following:
XeF4
Draw structure and name the shape of bromine trifluoride.
Which of the following fluorides does not exist?
Helium is preferred to be used in balloons instead of hydrogen because it is ____________.
Substance having the lowest boiling point ______.
The atomic radii of Zr and Hf are almost identical. This is because of
Noble gases are named because of their inertness towards reactivity. Identify an incorrect statement about them.
Which one of the following reactions of xenon compounds is not feasible?
Discuss the trends in electronegativity and atomic radii for elements of group 16 17, 18.
