Advertisements
Advertisements
प्रश्न
How are xenon fluorides XeF2, XeF4 and XeF6 obtained?
Advertisements
उत्तर
Xenon fluorides are obtained by the direct reaction of xenon (Xe) with fluorine gas (F2). The product formed depends on the reaction conditions, such as temperature, pressure, and the ratio of Xe to F2:
1. Formation of XeF2:
\[\ce{Xe + F2 -> XeF2}\] (673 K, 1 bar, excess Xe)
2. Formation of XeF4:
\[\ce{Xe + 2F2 -> XeF4}\] (873 K, 7 bar, 1 : 5 ratio)
3. Formation of XeF6:
\[\ce{Xe + 3F2 -> XeF6}\] (573 K, 60–70 bar, 1:20 ratio)
संबंधित प्रश्न
Draw the structure of the following molecule:
XeF4
Account for the following:
Helium is used in diving apparatus.
Complete the following equation:
\[\ce{XeF2 + H2O ->}\]
test q 1234
Balance the following equation:
\[\ce{XeF6 + H2O -> XeO2F2 + HF}\]
Why has it been difficult to study the chemistry of radon?
How are XeO3 and XeOF4 prepared?
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{ICI^-_4}\]
Complete the given chemical equations:
`2XeF_2 + 2H_2O->`
Complete the following reactions : XeF6 + 3H2O →
Write the electronic configuration of the following element:
Krypton (Z = 36)
The number of lone pairs of electrons present in ClF5:
Which of the following fluorides does not exist?
In which of the following pairs, the two species are isostructural:
On partial hydrolysis, XeF6 gives ______.
Write two uses of neon.
