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प्रश्न
How are XeO3 and XeOF4 prepared?
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उत्तर
XeO3 can be prepared in two ways as shown.
`6XeF_4 + 12H_2O -> 4Xe + 2XeO_3 + 24HF + 3O_2`
`XeF_6 + 3H_2O -> XeO_3 + 6HF`
XeOF4 can be prepared using XeF6
`XeF_6 + H_2O -> XeOF_4+2HF`
संबंधित प्रश्न
Draw the structure of the following molecule:
XeF4
Draw the structures of the following molecules: XeF2
Complete the following equations : XeF4 + O2F2→
test q 1234
Which one of the following does not exist?
Give the formula and describe the structure of a noble gas species which is isostructural with:
\[\ce{IBr^-_2}\]
Complete the following reactions:
XeF6+2H2O ----->
Write the electronic configuration of the following element:
Krypton (Z = 36)
Draw the structure of XeF4.
Explain the trend in the following atomic properties of group 16 elements:
Electron gain enthalpy
Partial hydrolysis of XeF4 gives ____________.
Substance having the lowest boiling point ______.
On partial hydrolysis, XeF6 gives ______.
The atomic radii of Zr and Hf are almost identical. This is because of
Noble gases are named because of their inertness towards reactivity. Identify an incorrect statement about them.
Match List - I with List - II:
| List - I | List - II | ||
| (Species) | (Number of lone pairs of electrons on the central atom) |
||
| (A) | XeF2 | (i) | 0 |
| (B) | XeO2F2 | (ii) | 1 |
| (C) | XeO3F2 | (iii) | 2 |
| (D) | XeF4 | (iv) | 3 |
Choose the most appropriate answer from the options given below:
\[\ce{XeF4 + H2O - \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}}\]
