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What is the Distance Between the Points (5 Sin 60°, 0) and (0, 5 Sin 30°)?

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Question

What is the distance between the points (5 sin 60°, 0) and (0, 5 sin 30°)?

 
Short/Brief Note
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Solution

We have to find the distance between A(5 sin 60° , 0) and B ( 0,5 sin 30° ) .

In general, the distance between A`(x_1 , y_1)`  and B`(x_2 ,y_2)` is given by,

`AB = sqrt((x_2 - x_1 )^2 + (y_2 - y_1)^2)`

So,

`AB = sqrt((5 sin 60° - 0)^2 + (0- 5 sin 30°)^2)`

But according to the trigonometric identity,

`sin^2 theta + cos^2 theta = 1`

And,

`sin 30° = cos 60°`

Therefore,

`AB = sqrt( 5^2 ( sin^2 60° + cos^2 60°) `

       = 5  

 

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Chapter 6: Co-ordinate Geometry - Exercise 6.6 [Page 61]

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R.D. Sharma Mathematics [English] Class 10
Chapter 6 Co-ordinate Geometry
Exercise 6.6 | Q 4 | Page 61

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