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Question
Using suitable identity, find the value of (1.1)3.
Sum
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Solution
Given: Find the value of (1.1)3 using a suitable algebraic identity.
Step-wise calculation:
1. Recognize that (1.1 = 1 + 0.1), so we can use the binomial cube identity:
(1 + x)3 = 13 + 3 × 12 × x + 3 × 1 × x2 + x3
(1 + x)3 = 1 + 3x + 3x2 + x3
where (x = 0.1).
2. Substitute (x = 0.1) into the identity:
(1.1)3 = 1 + 3(0.1) + 3(0.1)2 + (0.1)3
3. Calculate each term:
3(0.1) = 0.3
3(0.1)2 = 3 × 0.01
3(0.1)2 = 0.03
(0.1)3 = 0.001
4. Add these values together:
1 + 0.3 + 0.03 + 0.001 = 1.331
Thus, the value of (1.1)3 using the binomial identity is 1.331.
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Chapter 3: Expansions - Exercise 3A [Page 64]
