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Question
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(x + 5)(x + 6)(x + 7)
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Solution
(x + 5)(x + 6)(x + 7)
(x + a)(x + b)(x + c) ≡ x3 + (a + b + c)x2 + (ab + bc + ca)x + abc
Co-efficient of x2 = a + b + c = 5 + 6 + 7 = 18
Co-efficient of x2 = ab + bc + ca
= (5 × 6) + (6 × 7) + (7 × 5)
= 30 + 42 + 35
= 107
Constant term = abc = 5 × 6 × 7
Co-efficient of constant term = 210
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