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Question
Perform the following division:
(3pqr – 6p2q2r2) ÷ 3pq
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Solution
We have,
`(3pqr - 6p^2q^2r^2) ÷ 3pq = (3pqr - 6p^2q^2r^2)/(3pq)`
= `(3pqr)/(3pq) - (6p^2q^2r^2)/(3pq)`
= `r - (2 xx 3 xx p xx p xx q xx q xx r xx r)/(3 xx p xx q)`
= r – 2pqr2
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