Advertisements
Advertisements
Question
Perform the following division:
(3pqr – 6p2q2r2) ÷ 3pq
Advertisements
Solution
We have,
`(3pqr - 6p^2q^2r^2) ÷ 3pq = (3pqr - 6p^2q^2r^2)/(3pq)`
= `(3pqr)/(3pq) - (6p^2q^2r^2)/(3pq)`
= `r - (2 xx 3 xx p xx p xx q xx q xx r xx r)/(3 xx p xx q)`
= r – 2pqr2
APPEARS IN
RELATED QUESTIONS
If 2x + 3y = 14 and 2x − 3y = 2, find the value of xy.
[Hint: Use (2x + 3y)2 − (2x − 3y)2 = 24xy]
Find the following product: (y2 + 12) (y2 + 6)
Evaluate the following: 102 × 106
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(x + 5)(x + 6)(x + 7)
Simplify:
`(7/9 a + 9/7 b)^2 - ab`
Simplify:
(ab – c)2 + 2abc
Expand the following, using suitable identities.
`((2x)/3 - 2/3)((2x)/3 + (2a)/3)`
Expand the following, using suitable identities.
`((2a)/3 + b/3)((2a)/3 - b/3)`
Carry out the following division:
76x3yz3 ÷ 19x2y2
Perform the following division:
(– qrxy + pryz – rxyz) ÷ (– xyz)
