Advertisements
Advertisements
Question
If (x + y + z) = 9 and (xy + yz + zx) = 26, then find the value of x2 + y2 + z2
Advertisements
Solution
(x + y + z) = 9 and (xy + yz + zx) = 26
x2 + y2 + z2 = (x + y + z)2 – 2(xy + yz + zx)
= 92 – 2 × 26
= 81 – 52
= 29
APPEARS IN
RELATED QUESTIONS
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: 1.8 × 2.2
Simplify the following using the identities: \[\frac{{58}^2 - {42}^2}{16}\]
Find the following product: (x − 3) ( x − 2)
Find the following product: \[\left( y^2 + \frac{5}{7} \right)\left( y^2 - \frac{14}{5} \right)\]
Multiply the following:
(3x2 + 4x – 8), (2x2 – 4x + 3)
Simplify:
(s2t + tq2)2 – (2stq)2
Expand the following, using suitable identities.
`(4/5p + 5/3q)^2`
Expand the following, using suitable identities.
`((2a)/3 + b/3)((2a)/3 - b/3)`
Expand the following, using suitable identities.
(7x + 5)2
Perform the following division:
(– qrxy + pryz – rxyz) ÷ (– xyz)
