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Question
If (x + y + z) = 9 and (xy + yz + zx) = 26, then find the value of x2 + y2 + z2
Sum
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Solution
(x + y + z) = 9 and (xy + yz + zx) = 26
x2 + y2 + z2 = (x + y + z)2 – 2(xy + yz + zx)
= 92 – 2 × 26
= 81 – 52
= 29
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