Advertisements
Advertisements
प्रश्न
If (x + y + z) = 9 and (xy + yz + zx) = 26, then find the value of x2 + y2 + z2
Advertisements
उत्तर
(x + y + z) = 9 and (xy + yz + zx) = 26
x2 + y2 + z2 = (x + y + z)2 – 2(xy + yz + zx)
= 92 – 2 × 26
= 81 – 52
= 29
APPEARS IN
संबंधित प्रश्न
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: 1.8 × 2.2
Simplify the following using the identities: 178 × 178 − 22 × 22
Find the following product: (x − 11) (x + 4)
Find the following product: \[\left( x + \frac{4}{3} \right)\left( x + \frac{3}{4} \right)\]
Simplify: (2a + 3b + 4c) (4a2 + 9b2 + 16c2 – 6ab – 12bc – 8ca)
Simplify:
(3x + 2y)2 + (3x – 2y)2
Simplify:
(ab – c)2 + 2abc
Expand the following, using suitable identities.
`(4/5a + 5/4b)^2`
Using suitable identities, evaluate the following.
(98)2
Match the expressions of column I with that of column II:
| Column I | Column II |
| (1) (21x + 13y)2 | (a) 441x2 – 169y2 |
| (2) (21x – 13y)2 | (b) 441x2 + 169y2 + 546xy |
| (3) (21x – 13y)(21x + 13y) | (c) 441x2 + 169y2 – 546xy |
| (d) 441x2 – 169y2 + 546xy |
