Advertisements
Advertisements
प्रश्न
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(x + 5)(x + 6)(x + 7)
Advertisements
उत्तर
(x + 5)(x + 6)(x + 7)
(x + a)(x + b)(x + c) ≡ x3 + (a + b + c)x2 + (ab + bc + ca)x + abc
Co-efficient of x2 = a + b + c = 5 + 6 + 7 = 18
Co-efficient of x2 = ab + bc + ca
= (5 × 6) + (6 × 7) + (7 × 5)
= 30 + 42 + 35
= 107
Constant term = abc = 5 × 6 × 7
Co-efficient of constant term = 210
APPEARS IN
संबंधित प्रश्न
Show that `(4pq + 3q)^2 - (4pq - 3q)^2 = 48pq^2`
Evaluate the following: 102 × 106
By using identity evaluate the following:
`1 + 1/8 - 27/8`
On dividing p(4p2 – 16) by 4p(p – 2), we get ______.
Using suitable identities, evaluate the following.
(98)2
Using suitable identities, evaluate the following.
(1005)2
Using suitable identities, evaluate the following.
52 × 53
Carry out the following division:
17ab2c3 ÷ (–abc2)
Carry out the following division:
–121p3q3r3 ÷ (–11xy2z3)
Perform the following division:
(– qrxy + pryz – rxyz) ÷ (– xyz)
