Advertisements
Advertisements
प्रश्न
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(x + 5)(x + 6)(x + 7)
Advertisements
उत्तर
(x + 5)(x + 6)(x + 7)
(x + a)(x + b)(x + c) ≡ x3 + (a + b + c)x2 + (ab + bc + ca)x + abc
Co-efficient of x2 = a + b + c = 5 + 6 + 7 = 18
Co-efficient of x2 = ab + bc + ca
= (5 × 6) + (6 × 7) + (7 × 5)
= 30 + 42 + 35
= 107
Constant term = abc = 5 × 6 × 7
Co-efficient of constant term = 210
APPEARS IN
संबंधित प्रश्न
Find the value of x, if 14x = (47)2 − (33)2.
Find the following product: (x + 7) (x − 5)
Find the following product: (y2 + 12) (y2 + 6)
Evaluate the following: 35 × 37
Evaluate the following by using identities:
983
Simplify:
(b2 – 49)(b + 7) + 343
Simplify:
(s2t + tq2)2 – (2stq)2
Expand the following, using suitable identities.
(x + 3)(x + 7)
Using suitable identities, evaluate the following.
(103)2
Using suitable identities, evaluate the following.
105 × 95
