Advertisements
Advertisements
प्रश्न
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(x + 5)(x + 6)(x + 7)
Advertisements
उत्तर
(x + 5)(x + 6)(x + 7)
(x + a)(x + b)(x + c) ≡ x3 + (a + b + c)x2 + (ab + bc + ca)x + abc
Co-efficient of x2 = a + b + c = 5 + 6 + 7 = 18
Co-efficient of x2 = ab + bc + ca
= (5 × 6) + (6 × 7) + (7 × 5)
= 30 + 42 + 35
= 107
Constant term = abc = 5 × 6 × 7
Co-efficient of constant term = 210
APPEARS IN
संबंधित प्रश्न
Show that (3x + 7)2 − 84x = (3x − 7)2
Show that (9p - 5q)2 + 180pq = (9p + 5q)2
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: (82)2 − (18)2
Find the following product: (3x − 4y) (2x − 4y)
On dividing 57p2qr by 114pq, we get ______.
Expand the following, using suitable identities.
`((2x)/3 - 2/3)((2x)/3 + (2a)/3)`
Expand the following, using suitable identities.
`((2a)/3 + b/3)((2a)/3 - b/3)`
Expand the following, using suitable identities.
(0.9p – 0.5q)2
Using suitable identities, evaluate the following.
52 × 53
Match the expressions of column I with that of column II:
| Column I | Column II |
| (1) (21x + 13y)2 | (a) 441x2 – 169y2 |
| (2) (21x – 13y)2 | (b) 441x2 + 169y2 + 546xy |
| (3) (21x – 13y)(21x + 13y) | (c) 441x2 + 169y2 – 546xy |
| (d) 441x2 – 169y2 + 546xy |
