Advertisements
Advertisements
प्रश्न
Show that (a - b)(a + b) + (b - c) (b + c) + (c - a) (c + a) = 0
Advertisements
उत्तर
L.H.S = (a - b) (a + b) + (b - c) (b + c) + (c - a) (c + a)
= (a2 - b2) + (b2 - c2) + (c2 - a2) = 0 = R.H.S
संबंधित प्रश्न
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: (79)2 − (69)2
Simplify the following using the identities: 178 × 178 − 22 × 22
Find the following product: (x − 11) (x + 4)
Find the following product: (p2 + 16) \[\left( p^2 - \frac{1}{4} \right)\]
Expand the following, using suitable identities.
(x + 3)(x + 7)
Using suitable identities, evaluate the following.
(52)2
Using suitable identities, evaluate the following.
(98)2
Using suitable identities, evaluate the following.
105 × 95
Carry out the following division:
76x3yz3 ÷ 19x2y2
Carry out the following division:
–121p3q3r3 ÷ (–11xy2z3)
