Advertisements
Advertisements
प्रश्न
Show that (a - b)(a + b) + (b - c) (b + c) + (c - a) (c + a) = 0
Advertisements
उत्तर
L.H.S = (a - b) (a + b) + (b - c) (b + c) + (c - a) (c + a)
= (a2 - b2) + (b2 - c2) + (c2 - a2) = 0 = R.H.S
संबंधित प्रश्न
Show that `(4pq + 3q)^2 - (4pq - 3q)^2 = 48pq^2`
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: (467)2 − (33)2
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: (79)2 − (69)2
Find the following product: (x + 4) (x + 7)
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(x + 5)(x + 6)(x + 7)
Simplify: (2a + 3b + 4c) (4a2 + 9b2 + 16c2 – 6ab – 12bc – 8ca)
Multiply the following:
(2x – 2y – 3), (x + y + 5)
Expand the following, using suitable identities.
(2x – 5y)(2x – 5y)
Using suitable identities, evaluate the following.
(52)2
Using suitable identities, evaluate the following.
(103)2
