Advertisements
Advertisements
प्रश्न
Simplify: (2a + 3b + 4c) (4a2 + 9b2 + 16c2 – 6ab – 12bc – 8ca)
Advertisements
उत्तर
(2a + 36 + 4c) (4a2 + 9b2 + 16c2 – 6ab – 12bc – 12bc – 8ca)
We know that
(a + b + c)(a2 + b2 + c2 – ab – bc – ca) = a3 + b3 + c3 × 3 abc
∴ (2a + 36 + 4c)(4a2 + 9b2 + 16 c2 – 6 ab – 12 bc – 8 ca)
= (2a)3 + (3b)3 + (4c)3 – 3 × 2a × 36 × 4c
= 8a3 + 27b3 + 64c3 – 72 abc
APPEARS IN
संबंधित प्रश्न
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: (82)2 − (18)2
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: 1.8 × 2.2
Simplify the following using the identities: \[\frac{198 \times 198 - 102 \times 102}{96}\]
Find the following product: (3x2 − 4xy) (3x2 − 3xy)
Evaluate the following: 35 × 37
Expand the following:
(3a + 1) (3a – 2) (3a + 4)
If (x + y + z) = 9 and (xy + yz + zx) = 26, then find the value of x2 + y2 + z2
Simplify:
(2.5m + 1.5q)2 + (2.5m – 1.5q)2
Expand the following, using suitable identities.
(7x + 5)2
Carry out the following division:
17ab2c3 ÷ (–abc2)
