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Question
Show that (a - b)(a + b) + (b - c) (b + c) + (c - a) (c + a) = 0
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Solution
L.H.S = (a - b) (a + b) + (b - c) (b + c) + (c - a) (c + a)
= (a2 - b2) + (b2 - c2) + (c2 - a2) = 0 = R.H.S
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