Show that (A - B)(A + B) + (B - C) (B + C) + (C - A) (C + A) = 0

Show that (a - b)(a + b) + (b - c) (b + c) + (c - a) (c + a) = 0

L.H.S = (a - b) (a + b) + (b - c) (b + c) + (c - a) (c + a)

= (a² - b²) + (b² - c²) + (c² - a²) = 0 = R.H.S

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