Advertisements
Advertisements
Question
Show that (a - b)(a + b) + (b - c) (b + c) + (c - a) (c + a) = 0
Advertisements
Solution
L.H.S = (a - b) (a + b) + (b - c) (b + c) + (c - a) (c + a)
= (a2 - b2) + (b2 - c2) + (c2 - a2) = 0 = R.H.S
APPEARS IN
RELATED QUESTIONS
Show that (3x + 7)2 − 84x = (3x − 7)2
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: (82)2 − (18)2
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: 197 × 203
Find the value of x, if 14x = (47)2 − (33)2.
Find the following product: \[\left( z + \frac{3}{4} \right)\left( z + \frac{4}{3} \right)\]
Evaluate the following: 102 × 106
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(2x + 3)(2x – 5)(2x – 6)
By using identity evaluate the following:
73 – 103 + 33
Expand the following, using suitable identities.
(x2y – xy2)2
Using suitable identities, evaluate the following.
105 × 95
