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Question
Unequal masses will not balance on a fulcrum if they are at equal distance from it; one side will go up and the other side will go down.
Unequal masses will balance when the following proportion is true:
`("mass"1)/("length"2) = ("mass"2)/("length"1)`
Two children can be balanced on a seesaw when
`("mass"1)/("length"2) = ("mass"2)/("length"1)`. The child on the left and child on the right are balanced. What is the mass of the child on the right?
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Solution
It is given that, for balancing.
`("Mass" 1)/("Length" 2) = ("Mass" 2)/("Length" 1)`
According to the question,
Mass 1 = 24 kg, length 1 = 3 m and length 2 = 2 m
∴ `24/2 = ("Mass" 2)/3` ...[By cross-multiplication]
⇒ Mass 2 = `(24 xx 3)/2` = 36 kg
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