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Question
Two sources of sound S1 and S2 vibrate at same frequency and are in phase. The intensity of sound detected at a point P as shown in the figure is I0. (a) If θ equals 45°, what will be the intensity of sound detected at this point if one of the sources is switched off? (b) What will be the answer of the previous part if θ = 60°?
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Solution
Given:
Resultant intensity at P = I0
The two sources of sound S1 and S2 vibrate with the same frequency and are in the same phase.
(a) When θ = 45°:
Path difference = S1P − S2P = 0
So, when the source is switched off, the intensity of sound at P is \[\frac{I_0}{4}\] .
(b) When θ = 60°, the path difference is also 0. Similarly, it can be proved that the intensity at P is \[\frac{I_0}{4}\]
when the source is switched off.
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