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Karnataka Board PUCPUC Science Class 11

Find the Fundamental, First Overtone and Second Overtone Frequencies of an Open Organ Pipe of Length 20 Cm. Speed of Sound in Air is 340 Ms−1.

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Question

Find the fundamental, first overtone and second overtone frequencies of an open organ pipe of length 20 cm. Speed of sound in air is 340 ms−1.

Sum
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Solution

Given:
Speed of sound in air v = 340 m/s
Length of open organ pipe L = 20 cm = 20 × 10−2 m
Fundamental frequency \[\left( f \right)\] of an open organ pipe :

\[f = \left( \frac{v}{2L} \right) = \frac{340}{2 \times 20 \times {10}^{- 2}}=850\text { Hz }\]

First overtone frequency \[\left( f_1 \right)\] : 

f1 = \[2f\]

\[\Rightarrow  f_1  = \left( \frac{2V}{2I} \right) = 2 \times 850 = 1700 \text{ Hz }\]

Second overtone frequency \[\left( f_2 \right)\] : 

\[f_2  = 3f\]\[ \Rightarrow  f_2  = 3\left( \frac{V}{2L} \right) = 3 \times 850 = 2550  \text { Hz }\]

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Chapter 16: Sound Waves - Exercise [Page 355]

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HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 16 Sound Waves
Exercise | Q 36 | Page 355

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