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Question
Two natural numbers differ by 6 and their sum is 36. Find the larger number.
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Solution
∵ Difference between two numbers = 6
and their sum = 36
Let first natural number = x
The second number = x - 6
∴ x + x - 6 = 36
⇒ 2x = 36 + 6 = 42
x = `42/2 = 21`
∴ Larger number = 21
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