Question

Two natural numbers differ by 6 and their sum is 36. Find the larger number.

Answer 1

∵ Difference between two numbers = 6

and their sum = 36

Let first natural number = x

The second number = x - 6

∴ x + x - 6 = 36

⇒ 2x = 36 + 6 = 42

x = `42/2 = 21`

∴ Larger number = 21