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Question
Two metals X and Y form the salts XSO4 and Y2SO4, respectively. The solution of salt XSO4 is blue in colour whereas that of Y2SO4 is colourless. When barium chloride solution is added to XSO4 solution, then a white precipitate Z is formed along with a salt which turns the solution green. And when barium chloride solution is added to Y2SO4 solution, then the same white precipitate Z is formed along with colourless common salt solution.
- What could the metals X and Y be?
- Write the name and formula of salt XSO4.
- Write the name and formula of salt Y2SO4.
- What is the name and formula of white precipitate Z?
- Write the name and formula of the salt which turns the solution green in the first case.
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Solution
- Metal X is copper (Cu) and metal Y is Sodium (Na).
- Salt XSO4 is copper sulphate, having the formula CuSO4.
- Salt Y2SO4 is sodium sulphate, having the formula Na2SO4.
- Precipitate Z is barium sulphate, having the formula BaSO4.
- The salt which turns the solution green in the first case is copper(II) chloride, having the formula CuCl2.
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