Question

Two metals X and Y form the salts XSO₄ and Y₂SO₄, respectively. The solution of salt XSO₄ is blue in colour whereas that of Y₂SO₄ is colourless. When barium chloride solution is added to XSO₄ solution, then a white precipitate Z is formed along with a salt which turns the solution green. And when barium chloride solution is added to Y₂SO₄ solution, then the same white precipitate Z is formed along with colourless common salt solution.

1. What could the metals X and Y be?
2. Write the name and formula of salt XSO₄.
3. Write the name and formula of salt Y₂SO₄.
4. What is the name and formula of white precipitate Z?
5. Write the name and formula of the salt which turns the solution green in the first case.

Answer 1

1. Metal X is copper (Cu) and metal Y is Sodium (Na).
2. Salt XSO₄ is copper sulphate, having the formula CuSO₄.
3. Salt Y₂SO₄ is sodium sulphate, having the formula Na₂SO₄.
4. Precipitate Z is barium sulphate, having the formula BaSO₄.
5. The salt which turns the solution green in the first case is copper(II) chloride, having the formula CuCl₂.