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Question
Two cells each having an e.m.f. of 2 V and an internal resistance of \(2,\Omega\) are connected in parallel as shown in Fig. What is the current flowing through the circuit in each case?
Numerical
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Solution
Given: EMF of each cell, \(E=2\,V\)
Internal resistance of each cell, \(r=2\,\Omega\)
External resistance, \(R=4\,\Omega\)
When cells are connected in series,
Total EMF:
\[ E_{\text{total}}=2+2=4\,V \]
= 4 V
Total internal resistance:
\[ r_{\text{total}}=2+2\]
= 4 Ω
Current flowing:
\[ I=\frac{E}{R+r}\]
\[ =\frac{4}{4+4} \]
\[{=0.5\,A}\]
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