Question

Truth table for the given circuit (Figure) is ______.

Options

• A	B	E
  0	0	1
  0	1	0
  1	0	1
  1	1	0

• A	B	E
  0	0	1
  0	1	0
  1	0	0
  1	1	1

• A	B	E
  0	0	1
  0	1	1
  1	0	0
  1	1	1

• A	B	E
  0	0	0
  0	1	1
  1	0	1
  1	1	0

Answer 1

A	B	E
0	0	1
0	1	1
1	0	0
1	1	1

Explanation:

In this problem, the input C of the OR gate is an output of the AND gate. So, “C equals A AND B” or C = A · B and “D equals Not A AND B” or D = Ā · B and “E equals C AND D" or E = C + D = (A · B) + (A · B)

Now we can generate the truth table of this arrangement of gates can be given by

A	B	Ā	C = A · B	d = Ā · B	E = (C + D)
0	0	1	0	0	0
0	1	1	0	1	1
1	0	0	0	0	0
1	1	1	1	0	1