Question

Total number of electrons present in 1.7 g of ammonia is

Options

• 6.022 × 10²³

• `(6.022 xx 10^22)/1.7`

• `(6.022 xx 10^24)/1.7`

• `(6.022 xx 10^23)/1.7`

Answer 1

6.022 × 10²³

Explanation:

No. of electrons present in one ammonia (NH₃) molecule (7 + 3) = 10

No. of moles of ammonia = `"Mass"/"Molar mass"`

= `(1.7  "g")/(17  "gmol"^-1)`

= 0.1 mol

No. of molecules present in 0.1 mol of ammonia

= 0.1 × 6.022 × 10²³

= 6.022 × 10²²

No. of electrons present in 0.1 mol of ammonia

= 10 × 6.022 × 10²²

= 6.022 × 10²³