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Karnataka Board PUCPUC Science Class 11

Three Observers A, B and C Measure the Speed of Light Coming from a Source to Be νA, νBand νC.

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Question

Three observers A, B and C measure the speed of light coming from a source to be νA, νBand νC. A moves towards the source and C moves away from the source at the same speed. B remains stationary. The surrounding space is water everywhere.

(a) \[\nu_A  >  \nu_B  >  \nu_C\]

(b) \[\nu_A  <  \nu_B  <  \nu_C\]

(c) \[\nu_A  =  \nu_B  =  \nu_C\]

(d) \[\nu_B  = \frac{1}{2}\left( \nu_A + \nu_C \right)\]

Short/Brief Note
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Solution

(a) \[\nu_A  >  \nu_B  >  \nu_C\]

(d) \[\nu_B  = \frac{1}{2}\left( \nu_A + \nu_C \right)\]

 

In any other medium, the speed of light is given by \[v = c/\eta,\] where \[\eta \] is the refractive index of the medium and according to Doppler effect,  for an observer moving towards the source ,speed of light appears to be  more than the other two cases. On the other hand, it will be least when the observer is moving away from the source.

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Chapter 17: Light Waves - MCQ [Page 380]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 17 Light Waves
MCQ | Q 6 | Page 380

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Three observers A, B and C measure the speed of light coming from a source to be νA, νBand νC. A moves towards the source and C moves away from the source at the same speed. B remains stationary. The surrounding space is vacuum everywhere.

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(b) \[\nu_A  <  \nu_B  <  \nu_C\]

(c) \[\nu_A  =  \nu_B  =  \nu_C\]

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