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There is a Continuous Growth in Population of a Village at the Rate of 5% per Annum. If Its Present Population is 9261, What It Was 3 Years Ago?

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Question

There is a continuous growth in population of a village at the rate of 5% per annum. If its present population is 9261, what it was 3 years ago?

Sum
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Solution

Population after three years = P \[\left( 1 + \frac{R}{100} \right)^n \]
\[9, 261 = P \left( 1 + \frac{5}{100} \right)^3 \]
\[9, 261 = P \left( 1 . 05 \right)^3 \]
\[P = \frac{9, 261}{1 . 157625}\]
\[ = 8, 000\]
Thus, the population three years ago was 8, 000.

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Chapter 14: Compound Interest - Exercise 14.4 [Page 27]

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R.D. Sharma Mathematics [English] Class 8
Chapter 14 Compound Interest
Exercise 14.4 | Q 5 | Page 27

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