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The Count of Bacteria in a Culture Grows by 10% in the First Hour, Decreases by 8% in the Second Hour and Again Increases by 12% in the Third Hour. If the Count of Bacteria in the Sample is 13125000,

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Question

The count of bacteria in a culture grows by 10% in the first hour, decreases by 8% in the second hour and again increases by 12% in the third hour. If the count of bacteria in the sample is 13125000, what will be the count of bacteria after 3 hours?

Sum
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Solution

\[Given: \]
\[ R_1 = 10 % \]
\[ R_2 = - 8 % \]
\[ R_3 = 12 % \]
P = Original count of bacteria = 13, 125, 000
We know that: 
\[P\left( 1 + \frac{R_1}{100} \right)\left( 1 - \frac{R_2}{100} \right)\left( 1 + \frac{R_3}{100} \right)\]
∴ Bacteria count after three hours \[= 13, 125, 000\left( 1 + \frac{10}{100} \right)\left( 1 - \frac{8}{100} \right)\left( 1 + \frac{12}{100} \right)\]
\[ = 13, 125, 000\left( 1 . 10 \right)\left( 0 . 92 \right)\left( 1 . 12 \right)\]
\[ = 14, 876, 400\]
Thus, the bacteria count after three hours will be 14, 876, 400.

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Chapter 14: Compound Interest - Exercise 14.4 [Page 27]

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RD Sharma Mathematics [English] Class 8
Chapter 14 Compound Interest
Exercise 14.4 | Q 9 | Page 27

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